Answer to Question #40175 in Inorganic Chemistry for Farhan Mutlib

Question #40175
A saturated solution of BaF2 has 0.0200 g dissolved in 15.0 mL . M(BaF2) = 175.34 g mol–1 Calculate the solubility of BaF2 in mol L–1. s(BaF2) = 7.60427 × 10–3 mol L–1 Calculate the ion concentrations from the molar solubility. [Ba2+] = 7.60427 × 10–3 [F–] = 1.520854 × 10–2 Calculate Ks(BaF2). Ks(BaF2) = × 10–6 (3 sf) How do i work out Ks?
1
Expert's answer
2014-03-20T13:16:36-0400
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