Question #35842

helium is found to diffuse two times faster than x, what is the molecular mass of x?

Expert's answer

Grahams law, says:

v1/v2 = sqrt(M2/M1) where v1 and v2 are veloicityes;

M1 and M2 are molecular weights

So is difuse faster in two times

v1/v2 = 2

M(He) = 4 g/mol

2 = sqrt(x/4)

4 = x/4

x = 16 (g/mol)

Answer: 16 (g/mol)

v1/v2 = sqrt(M2/M1) where v1 and v2 are veloicityes;

M1 and M2 are molecular weights

So is difuse faster in two times

v1/v2 = 2

M(He) = 4 g/mol

2 = sqrt(x/4)

4 = x/4

x = 16 (g/mol)

Answer: 16 (g/mol)

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