Answer to Question #35712 in Inorganic Chemistry for sayanti mallick
In CaCl2 Ca is in ion form.
A calcium(II) ion, Ca2+, has 20 protons and 18 electrons because it has lost two (to give it the +2 charge).
p( Ca2+) = 20
e ( Ca2+) =20 - 2 = 18
n( Ca2+) = Ar ( Ca) - p( Ca2+)
n( Ca2+) = 40 - 20 = 20
Need a fast expert's response?Submit order
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!