Answer to Question #342877 in Inorganic Chemistry for Haheh

Question

2.50.00 mL of concentrated nitric acid (16M

HN03) is diluted to 1.000 L. What is the

concentration of the new solution?

Answer 1

Given:

c₁ = 16 M

V₁ = 50.00 mL = 0.050 L

c₂ = unknown

V₂ = 1.000 L

Solution:

where:

c₁, V₁ - the molarity and volume of the concentrated solution

c₂, V₂ - the molarity and volume of the diluted solution

Thus:

(16 M) × (0.050 L) = c₂ × (1.000 L)

c₂ = (16 M × 0.050 L) / (1.000 L) = 0.8 M

c₂ = 0.8 M

Answer: The concentration of the new solution is 0.8 M