calculate the ph of a buffer that is 0.120M in NaHCO3 and 0.190M in Na2CO3
pH = pKa + log[Base]/[Acid]
9.65 = 10.25 + log [Base]/[Acid] ------------------------- since it is in one litre, Molarity = grams / MolarMass & with the conj base Na2CO3 having 106 g / mole & withthe conj acid NaHCO3 having 84 g / mole
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