What is the molarity of a sodium hydroxide solution if 27.9 mL of this solution reacts exactly with 22.30 mL of 0.253 M sulfuric acid?
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Expert's answer
2013-07-16T11:07:58-0400
n(H2SO4) = Cm x V n(H2SO4) = 0.253 M x 0.02230 L = 0.00564 mol The balanced equation is: H2SO4 + 2NaOH = Na2SO4 + 2H2O the ratio between H2SO4 and NaOH is 1 : 2 n(NaOH) = 0.00564/2 = 0.00282 mol Cm(NaOH) = n(NaOH)/V(NaOH) Cm(NaOH) = 0.00282 mol/ 0.0250 L = 0.113 M
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