# Answer to Question #32309 in Inorganic Chemistry for tom

Question #32309

in a cilender8 inches in diameter and12 inches in length. another cilender inside the cilinder with a clesrence of 1 inch all around all sides.and closed to seal the top compleatly. on the bottom a small hole to inkect liquid nitrogin.pour liuqid into container,inject liquid nitrogin. how many seconds will it take to freeze liquid? such as water etc.

Expert's answer

The volume of water will be calculated by formula:

V = 3.1416 * r^2 * h

so, V = 4 x 4 x 3.1416 x 12 = 603.1872 cubic inches or 9.88 L of water will take to freeze when it starts at 25°C.

So energy needed to freeze is:

E = cm∆T

m = V , because the density of water is 1.

m = 9.88 kg

E = 4.17 J g

The amount of energy, that needed to freeze the water in one second is 60 J

So if we have 1029990 J of energy, we can calculate the time that needed to freeze the 9,88 L of water

It will be 1029990/60 = 17166.5 seconds

V = 3.1416 * r^2 * h

so, V = 4 x 4 x 3.1416 x 12 = 603.1872 cubic inches or 9.88 L of water will take to freeze when it starts at 25°C.

So energy needed to freeze is:

E = cm∆T

m = V , because the density of water is 1.

m = 9.88 kg

E = 4.17 J g

^{-1}K^{-1}x 9880g x 25°C = 1029990 JThe amount of energy, that needed to freeze the water in one second is 60 J

So if we have 1029990 J of energy, we can calculate the time that needed to freeze the 9,88 L of water

It will be 1029990/60 = 17166.5 seconds

**Answer:**17166.5 seconds will it take to freeze waterNeed a fast expert's response?

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