Question #32071

find the molarity of the solution in which there is 60grams of sodium hydroxide in two liters of solution.

Expert's answer

At first we should calculate the amount of substance (n) of sodium hydroxide:

n(subs.) = m(subs.)/M(subs.)

M(NaOH) = 23 + 16 + 1 = 40 g/mol

n(NaOH) = 60g/(40 g/mol) = 1,5 mol

We can obtain molarity (c) using formula:

c(substance) = n(substance)/V(solution)

c(NaOH) = 1,5 mol / 2 l = 0,75 mol∙l^{-1}

n(subs.) = m(subs.)/M(subs.)

M(NaOH) = 23 + 16 + 1 = 40 g/mol

n(NaOH) = 60g/(40 g/mol) = 1,5 mol

We can obtain molarity (c) using formula:

c(substance) = n(substance)/V(solution)

c(NaOH) = 1,5 mol / 2 l = 0,75 mol∙l

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