find the molarity of the solution in which there is 60grams of sodium hydroxide in two liters of solution.
At first we should calculate the amount of substance (n) of sodium hydroxide: n(subs.) = m(subs.)/M(subs.) M(NaOH) = 23 + 16 + 1 = 40 g/mol n(NaOH) = 60g/(40 g/mol) = 1,5 mol We can obtain molarity (c) using formula: c(substance) = n(substance)/V(solution) c(NaOH) = 1,5 mol / 2 l = 0,75 mol∙l-1
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