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Answer to Question #32071 in Inorganic Chemistry for imran

Question #32071
find the molarity of the solution in which there is 60grams of sodium hydroxide in two liters of solution.
Expert's answer
At first we should calculate the amount of substance (n) of sodium hydroxide:
n(subs.) = m(subs.)/M(subs.)
M(NaOH) = 23 + 16 + 1 = 40 g/mol
n(NaOH) = 60g/(40 g/mol) = 1,5 mol
We can obtain molarity (c) using formula:
c(substance) = n(substance)/V(solution)
c(NaOH) = 1,5 mol / 2 l = 0,75 mol∙l-1

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