# Answer on Inorganic Chemistry Question for samriddhi

Question #31475

r coloured metal (A) is added to dilute sulphuric acid, solution (B) is formed which is colourless solution and a gas (c) is evolved which is colourless name ‘A’, ‘B’ and ‘C’ and write the equation?

Expert's answer

There are three colored metals - gold, copper and caesium. Only caesium reacts with diluted sulfuric acid, according to following equation:

2Cs + H

The solution of Caesium Sulfate is formed.

Hence,

A is Caesium (Cs)

B is solution of Caesium Sulfate (Cs

C is Hydrogen (H

2Cs + H

_{2}SO_{4}= Cs_{2}SO_{4}+ H_{2}The solution of Caesium Sulfate is formed.

Hence,

A is Caesium (Cs)

B is solution of Caesium Sulfate (Cs

_{2}SO_{4})C is Hydrogen (H

_{2})Need a fast expert's response?

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