Answer to Question #30483 in Inorganic Chemistry for Alan
If Sb-150 loses an alpha particle, what is left?
This antimony isotope (Sb-150) does not exist, but if we assume it is real and it loses the one alpha particle, it would be according to next scheme:
150Sb51 ----> 4He2 + 146In49
Thus, the indium isotope is left.