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Answer to Question #28713 in Inorganic Chemistry for miguel
Question #28713
6NaClO¾ + Cr½O¾ æ 3Na½O + 2Cr(CIO¾)¾
Expert's answer
The excellent solubility in water allows it toreceive perchlorates of any metal. In our situation this metal is
Cr.
The chemical equation will be
6NaClO4 + Cr2O3 = 3Na2O + 2Cr(ClO4)3
We got the perchlorate of chromium and oxide of sodium. It is the
reaction of exchange.
Cr.
The chemical equation will be
6NaClO4 + Cr2O3 = 3Na2O + 2Cr(ClO4)3
We got the perchlorate of chromium and oxide of sodium. It is the
reaction of exchange.
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