Answer to Question #26600 in Inorganic Chemistry for ramya sarvani
which of the following is least soluble in water?
A)BaF2 B)SrF2 C)MgF2 D)CaF2
To know what of the substances is least soluble we have to compare their solubility products.
The least soluble substance has the lowest solubility product.
The dissociation equation is
MF2 = M2+ + 2F- , where M2+ is Ba2+, Sr2+, Mg2+, Ca2+
Ksp = [M2+][F-]2
Ksp(BaF2) = 1.7 x 10-6
Ksp(SrF2) = 2.5 x 10-9
Ksp(MgF2) = 6.4 x 10-9
Ksp(CaF2) = 4.0 x 10-11
Answer: The least soluble is CaF2