Answer to Question #26600 in Inorganic Chemistry for ramya sarvani
A)BaF2 B)SrF2 C)MgF2 D)CaF2
The least soluble substance has the lowest solubility product.
The dissociation equation is
MF2 = M2+ + 2F- , where M2+ is Ba2+, Sr2+, Mg2+, Ca2+
Ksp = [M2+][F-]2
Ksp(BaF2) = 1.7 x 10-6
Ksp(SrF2) = 2.5 x 10-9
Ksp(MgF2) = 6.4 x 10-9
Ksp(CaF2) = 4.0 x 10-11
Answer: The least soluble is CaF2
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