Answer to Question #26455 in Inorganic Chemistry for Beverly
If starting molarity is X M, and volume is 250 ml, the amount of compound is X*0.25 =0.25X mol.
The amount of compound in 35 ml is 0.035 L * X =0.035X. New amount (after adding) is 0.25X-0.035X =0,215X mol of compounds is still in the solution, even after adding new water.
So it is 0.215X mol in 250 ml, and it is 0.215X * 1000ml/250ml = 0.86X mol per one liter.
Molarity is 0.86X M
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