# Answer to Question #25969 in Inorganic Chemistry for Erin

Question #25969

A gas with an initial volume of 24.0 L at a pressure of 565 mmHg is compressed by a pressure increase of 0.25 Pa. What is the final volume (L) of the gas, assuming the temperature does not change?

Expert's answer

This question can be solved using the ideal gas law:

PV = nRT

But even if you have two different conditions the amount is the same (R and T is constants), so:

0.1333 kPa in 1 mmHg

75.3145 kPa in 565 mmHg

P

n = P

n = P

P

P

V

V

PV = nRT

But even if you have two different conditions the amount is the same (R and T is constants), so:

0.1333 kPa in 1 mmHg

75.3145 kPa in 565 mmHg

P

_{1}V_{1}= nRT_{1}n = P

_{1}V_{1}/RT_{1}n = P

_{2}V_{2}/RT_{2}P

_{1}V_{1}/RT_{1}= P_{2}V_{2}/RT_{2}P

_{1}V_{1}= P_{2}V_{2}V

_{2}= P_{1}V_{1}/P_{2}V

_{2}= 75.3145 * 24.0 L / 75.31475 = 24.0Need a fast expert's response?

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