Answer to Question #25969 in Inorganic Chemistry for Erin

Question

A gas with an initial volume of 24.0 L at a pressure of 565 mmHg is compressed by a pressure increase of 0.25 Pa. What is the final volume (L) of the gas, assuming the temperature does not change?

Answer 1

This question can be solved using the ideal gas law:

PV = nRT

But even if you have two different conditions the amount is the same (R and T is constants), so:

0.1333 kPa in 1 mmHg
75.3145 kPa in 565 mmHg

P₁V₁ = nRT₁
n = P₁V₁/RT₁
n = P₂V₂/RT₂
P₁V₁/RT₁ = P₂V₂/RT₂
P₁V₁ = P₂V₂
V₂ = P₁V₁/P₂

V₂ = 75.3145 * 24.0 L / 75.31475 = 24.0