Question #25890

why we add 3.3 gram when standard of hydrogen peroxide???

Expert's answer

From given mass it is possible to find amount:

Amount of H2O2 is n=3.3/(16*2 + 2*1)=0.097 mol

This amount can be used for preparing standard solution with some volume of water:

If volume is one L, the molarity is 0.097 mol/L =0.097M

So the goal of this process is to prepare standard solution of hydrogen peroxide with predicted molarity.

Amount of H2O2 is n=3.3/(16*2 + 2*1)=0.097 mol

This amount can be used for preparing standard solution with some volume of water:

If volume is one L, the molarity is 0.097 mol/L =0.097M

So the goal of this process is to prepare standard solution of hydrogen peroxide with predicted molarity.

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