Answer to Question #25697 in Inorganic Chemistry for Jaylan

Question

Calcute the pH of a 0.0001 M KOH solution?

Answer 1

pH = -lg [H⁺]

In a water solution the ion product for water is:
[H⁺][OH^-] = K_w= 1 x 10^-14

lg [H⁺] + lg [OH^-] = lg[10^-14]

pH + pOH = 14

pH – lg[OH^-] = 14

pH = 14 + lg[OH-]

c(OH^-) = c(KOH) = 0.0001 M

pH = 14 + lg 0.0001 = 10

Answer: pH = 10