Answer to Question #236947 in Inorganic Chemistry for san

Question #236947

3NaHCO3(aq)



1
Expert's answer
2021-09-15T02:39:01-0400

If you were considering 3NaHCO3 (which is sodium bicarbonate), then in Step 2 you would have counted 1 Na, 1 H, 1 C, and 3 O to take into account the subscripts.


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