Answer to Question #236001 in Inorganic Chemistry for Bub

Inorganic Chemistry

Question #236001

Calculate the number of moles of solute present in 255 mL of 0.250 M CaBr 2.

Expert's answer

Proportion:

0.250 mol – 1000 mL

x mol – 255 mL

"x = \\frac{0.250 \\times 255}{1000}= 0.06375 \\;mol"

Answer: 0.0637 mol

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