obtain the ΔH° of the following:
ΔH=ΔE+PΔV
or ΔE=ΔH−PΔV
PΔV=1 atm×22.4 L=22.4 L atm
=22.4×101.3 J=2307 J=2.31 kJ
∴ΔE=−154.4−2.31=−156.71 kJ
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