107 784
Assignments Done
100%
Successfully Done
In July 2024

# Answer to Question #22874 in Inorganic Chemistry for fari

Question #22874
0.02 mol of aluminum is is burned in oxygen and the product is reacted with 2.00 mol dm^-3 hydrochloric acid.
what is the minimum volume of acid that will be required for complete reaction?
1
2013-01-28T09:40:12-0500
There are two reactions in this task:

4Al + 3O2 = 2Al2O3

Al2O3 + 6HCl = 2AlCl3 + 3H2O

0.02 mol of aluminum can produce X mol of Al2O3

0.02 X
4Al + 3O2 = 2Al2O3
4
2

X = 0.02*2/4 = 0.01 mol
Than 0.01 mol of Al2O3 can react with Y mol of HCl

0.01 Y
Al2O3 + 6HCl = 2AlCl3 + 3H2O
1 6

Y = 0.06 mol

Concentration of given solution is 2 M
It means that there is 2 mol in one L, and you need to know the volume if
you have 0.06 mol

2 mol ---------- 1 L
0.06 mol------- V

V = 0.06*1/2 = 0.03 L (30 ml)

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Assignment Expert
25.02.14, 18:16

Dear Sujata Roy You're welcome. We are glad to be helpful. If you really liked our service please press like-button beside answer field. Thank you!

Giang
21.02.14, 17:01

Thank you very much !