Answer to Question #227909 in Inorganic Chemistry for Ama

Question #227909
How is the oxidation number of these Borane compound being calculated
B12H12, B6H6, B2H2,
1
Expert's answer
2021-08-22T07:30:36-0400

Hydrogen will be in +1 oxidation state , so Boron will be in -3 oxidation state. Hydrogen almost always remains in +1 oxidation state, the obvious exception being in metal hydrides.


6*1 = 6 .


Boron must therefore add to give -6 to balance. Since there are 2 Borons each is is in -3 oxidation state. This is expected as Boron is in group 3.


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