101 365
Assignments Done
99.5%
Successfully Done
In September 2021

# Answer to Question #227559 in Inorganic Chemistry for thasha

Question #227559

Lead metal is obtained from lead sulfide through the following reaction:

2PbS(s) + 2C(s) + 3O2(g) → 2Pb(s) +2CO(g) + 2SO2(g)

(a)If 100g of PbS is reacted with excess C and O2, calculate the mass of lead metal obtained.  ( 5 )

(b)Suppose 100 g of PbS is reacted with 4g of C and 20g O2.

Find the limiting reactant for this reaction.

( 4 )

(c)For question (b) above, calculate the mass of lead metal obtained.  ( 4 )

(d)By referring to the question (c) above, If 31.2g Pb is obtained as the yield. Calculate the percentage of yield.  ( 2 )

(e)Calculate mass of oxygen is needed to produce 500g of lead metal.

1
Expert's answer
2021-08-20T01:06:15-0400

Molar mass of PbS = 239.3

= 100/239.3

= 0.418 moles

Mole ratio = 2:2

= 0.418 moles of Pb

Molar mass of Pb = 207.2

= 207.2×0.418

= 86.59g

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

#### Comments

No comments. Be the first!

### Ask Your question

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS