ALuminum sulphide is produced from a reaction of the elements Al and S according to the reaction 2Al(s) + 3S(g) → Al2S3 . Given that the mass of aluminum is defined by a function mA such that t(mAl) = [ mAl 4.1
41/10 mAl ] and that t( mAl ) is a singular matrix. The mass of sulfur that reacted was equivalent to the POH of 3.981 x 10-7M solution of a base. What is the mass of the product formed?
A. 10.41g B. 102.6g C. 25.2g D. 40.5g