What is the molar concentration of a solution containing 10.0 g of NaOH in 250 mL of solution?
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Expert's answer
2013-01-17T10:39:40-0500
Themolar concentration of the solution can be found for the formula Cm = n / V(solution); So if we have 10.0 g of NaOH, we can find it's amount of substance n(NaOH) = m(NaOH) / M(NaOH); M(NaOH) = 23 + 16 + 1 = 40 g/mol; n(NaOH) = 10g / 40 g/mol = 0.25 moles So the molar concentration of solution will be Cm(NaOH) = 0.25 moles / 0.25 L = 1mol/L
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