Answer to Question #21730 in Inorganic Chemistry for Kailey
In a particular reaction between copper metal and silver nitrate, 12.7 g Cu produced 38.1 g Ag. What is the percent yield of silver in this reaction?
In this problem formula is:
so you have to find the theoretical :
moles of CU = grams/RMM = 12.7/63.55 = 0.200
moles of Ag = 0.200x2 (because the stiochemstry equations shows a 2:1ratio)= 0.4moles
grams = moles x Rmm = 0.4 x 107.9 = 43.16grams
so that's how we find the theoretical .. using the top equation
=(38.1/43.16)x100 = 88.39%
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