Question #21208

Q. One litre of CO2 is passed over hot coke. The volume becomes 1.4 litre. The composition of product is-
(i) 0.6 ltr CO (ii) 0.8 ltr of CO2 (iii)0.6 ltr of CO2 and 0.8 ltr of CO (iv) None

Expert's answer

Equation of the reaction:

CO_{2} + C = 2CO

According to equation, when 1 litre of CO_{2} reacts with 1 mol of coke, twolitres of CO are formed. Our mixture of gases has volume 1.4 L. Thus it is

composed from CO and non-reacted CO_{2}.

If x litres of CO_{2} are reacted, 2x liters of CO are formed. Total volume ofmixture is the sum of CO_{2} and CO volumes:

V(mixture) = V(new volume CO_{2}) + V(CO) = 1.4 L

V(new volume CO_{2}) = V(initial volume CO_{2}) - V(reacted CO_{2}) = (1 - x) L

V(CO) = 2x

So, we have equation:

1.4 = 1 - x + 2x

The solution is x = 0.4 L

Thus, the mixture consist from 1-0.4=0.6 L of CO2 and 2*0.4=0.8 L of CO (iii)

Answer: (iii)

The composition of product is 0.6 ltr of CO2 and 0.8 ltr of CO.

CO

According to equation, when 1 litre of CO

composed from CO and non-reacted CO

If x litres of CO

V(mixture) = V(new volume CO

V(new volume CO

V(CO) = 2x

So, we have equation:

1.4 = 1 - x + 2x

The solution is x = 0.4 L

Thus, the mixture consist from 1-0.4=0.6 L of CO2 and 2*0.4=0.8 L of CO (iii)

Answer: (iii)

The composition of product is 0.6 ltr of CO2 and 0.8 ltr of CO.

## Comments

Assignment Expert24.11.17, 20:51Dear visitor,

please use panel for submitting new questions

Kashish24.11.17, 18:35If volume of mixture of CO2 and CO increases by 20% on passing over hot cake, then what is the percentage of CO2 in the original mixture?

a)10%

b) 15%

c) 20%

d) 25%

Assignment Expert18.05.17, 15:20Dear Prachurjya Chuman Gogoi,

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Prachurjya Chuman Gogoi18.05.17, 15:14Good

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