Question #21208

Q. One litre of CO2 is passed over hot coke. The volume becomes 1.4 litre. The composition of product is-

(i) 0.6 ltr CO (ii) 0.8 ltr of CO2 (iii)0.6 ltr of CO2 and 0.8 ltr of CO (iv) None

(i) 0.6 ltr CO (ii) 0.8 ltr of CO2 (iii)0.6 ltr of CO2 and 0.8 ltr of CO (iv) None

Expert's answer

Equation of the reaction:

CO_{2} + C = 2CO

According to equation, when 1 litre of CO_{2} reacts with 1 mol of coke, twolitres of CO are formed. Our mixture of gases has volume 1.4 L. Thus it is

composed from CO and non-reacted CO_{2}.

If x litres of CO_{2} are reacted, 2x liters of CO are formed. Total volume ofmixture is the sum of CO_{2} and CO volumes:

V(mixture) = V(new volume CO_{2}) + V(CO) = 1.4 L

V(new volume CO_{2}) = V(initial volume CO_{2}) - V(reacted CO_{2}) = (1 - x) L

V(CO) = 2x

So, we have equation:

1.4 = 1 - x + 2x

The solution is x = 0.4 L

Thus, the mixture consist from 1-0.4=0.6 L of CO2 and 2*0.4=0.8 L of CO (iii)

Answer: (iii)

The composition of product is 0.6 ltr of CO2 and 0.8 ltr of CO.

CO

According to equation, when 1 litre of CO

composed from CO and non-reacted CO

If x litres of CO

V(mixture) = V(new volume CO

V(new volume CO

V(CO) = 2x

So, we have equation:

1.4 = 1 - x + 2x

The solution is x = 0.4 L

Thus, the mixture consist from 1-0.4=0.6 L of CO2 and 2*0.4=0.8 L of CO (iii)

Answer: (iii)

The composition of product is 0.6 ltr of CO2 and 0.8 ltr of CO.

## Comments

Assignment Expert24.11.17, 19:51Dear visitor,

please use panel for submitting new questions

Kashish24.11.17, 17:35If volume of mixture of CO2 and CO increases by 20% on passing over hot cake, then what is the percentage of CO2 in the original mixture?

a)10%

b) 15%

c) 20%

d) 25%

Assignment Expert18.05.17, 15:20Dear Prachurjya Chuman Gogoi,

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Prachurjya Chuman Gogoi18.05.17, 15:14Good

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