Q. One litre of CO2 is passed over hot coke. The volume becomes 1.4 litre. The composition of product is-
(i) 0.6 ltr CO (ii) 0.8 ltr of CO2 (iii)0.6 ltr of CO2 and 0.8 ltr of CO (iv) None
Equation of the reaction: CO2 + C = 2CO According to equation, when 1 litre of CO2 reacts with 1 mol of coke, twolitres of CO are formed. Our mixture of gases has volume 1.4 L. Thus it is composed from CO and non-reacted CO2. If x litres of CO2 are reacted, 2x liters of CO are formed. Total volume ofmixture is the sum of CO2 and CO volumes: V(mixture) = V(new volume CO2) + V(CO) = 1.4 L V(new volume CO2) = V(initial volume CO2) - V(reacted CO2) = (1 - x) L V(CO) = 2x So, we have equation: 1.4 = 1 - x + 2x The solution is x = 0.4 L Thus, the mixture consist from 1-0.4=0.6 L of CO2 and 2*0.4=0.8 L of CO (iii) Answer: (iii) The composition of product is 0.6 ltr of CO2 and 0.8 ltr of CO.