What is the Na+1 ion concentration (in moles per liter) when 0.0234 g Na2CO3 is dissolved in enough water to make 150. mL of solution?
The molar mass of Na2CO3 is 106 g/mol. The amount of Na2CO3 is n(Na2CO3) = m(Na2CO3) / M(Na2CO3) = 0.0234 g / 106 g/mol = 0.00022 mol. The molar concentration of Na2CO3 is c(Na2CO3) = n(Na2CO3) / V(solution) = 0.00022 mol / 0.150 L = 0.0015 M (moles/L) According to dissociation reaction below, the concentration of Na(+1) ion is twice more of concentration of Na2CO3. c(Na+) = 2 * c(Na2CO3) = 0.003 M. Na2CO3 = 2 Na(+) + CO3(2-) Answer: 0.003 M