Answer to Question #21122 in Inorganic Chemistry for Danielle Louise Akerson
The molar concentration of Na2CO3 is c(Na2CO3) = n(Na2CO3) / V(solution) = 0.00022 mol / 0.150 L = 0.0015 M (moles/L)
According to dissociation reaction below, the concentration of Na(+1) ion is twice more of concentration of Na2CO3. c(Na+) = 2 * c(Na2CO3) = 0.003 M.
Na2CO3 = 2 Na(+) + CO3(2-)
Answer: 0.003 M
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