If 0.007 g of KHP (molar mass = 204.23) requires 30.0 mL of NaOH upon titration, what is the normality of NaOH?
Normality (N) = m /V × 1/eq
= 0.007/0.03 × 1/Eq
= 39.997 × 0.2333
= 9.333
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