Question #199458

At standard temperature and pressure, how many L of fluorine gas (F_{2}) are there in 3.01 mol of it?

- 1.34 × 10
^{–1}L of F2 - 1.14 × 10
^{2}L of F_{2} - 6.74 × 10
^{1}L of F_{2} - 7.92 × 10
^{–2}L of F_{2}

_{which of the options ?}

Expert's answer

The no of litres found in 3.01 moles of fluorine=68.32241L

Given:

Moles of fluorine=3mol

To Find:

No of litres present in 3mol of Fluorine.

Step by Step by Explanation:

Formula used for calculating the volume of fluorine is achieved through ideal gas equation

According to Ideal Gas;

From this above equation, volume can be calculated as

Where V=Volume of the fluorine in litres

N=number of moles=3.01moles

R=Gas constant

Under standard conditions

T=Temperature of the gas=273K

P=Pressure of the gas

Substitute all the values in the above equation we get

Result:

Thus the no of litres found in 3.01 moles of fluorine gas is 68.32241L

= 6.74 × 10^{1} L of F_{2}

Learn more about our help with Assignments: Inorganic Chemistry

## Comments

## Leave a comment