what is the pH of 0.02 mole HCl added to one liter of acetic acid and sodium acetate
Mole of acetic acid = molarity×volume= 1mol
Mole of sodium acetate= 1×1=1
If we add 0.02 mil HCl then salt will react .
After addition of salt
Mole of salt= 1-0.02=0.08
Mole of acid= 1.02