Answer to Question #18686 in Inorganic Chemistry for pam
w(CaO) = M(CaO)/M(CaMg(CO3)2) x 100 %
M(CaMg(CO3)2) = 184 g/mol
M(CaO) = 56 g/mol
w(CaO) = 56/184 x 100% = 30.43 %
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