Answer to Question #183715 in Inorganic Chemistry for KAMVA

Question

1.       What volume of 0,250 mol⋅dm^–3 H₂SO₄ (sulfuric acid) will react with 42,4 cm³ of 1,50 mol⋅dm^-3 Na₂CO₃ (sodium carbonate)? (Hint: Write the balanced equation first.) 

Answer 1

H2SO4 + Na2CO3 =H2O + CO2 + Na2SO4

n(Na2CO3)=0.042×1.5=0.06mol

n(H2SO4)=n(Na2CO3)

V(Na2CO3)=0.06/0.250= 0.25l=250ml