Answer to Question #177225 in Inorganic Chemistry for nawrin

Question

calculate the empirical formula of a compound made up of C (48.7%) , H(8.1%) and O (43.2%) [ ar(C)= 12, Ar (H) = 1 and Ar (O)= 16 ]

Answer 1

$\bigstar$ We know the mass of C=12

H=1

O=16

$\bull$ Now solving

   

Moles in 100 g. C =4.05  H= 8.04   O=2.70 

Ratio  C= 1.50  H=2.98  O= 1.00 

Empirical formula

  $\boxed{C_3H_6O_2}$