A 1.397 L container of O2 at 773.6 mm Hg was connected to another evacuated container which had a volume of 1.030 L and separated by a valve. What was the final pressure in atmospheres if the valve was opened and the gas allowed to expand into the other container?
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Expert's answer
2012-10-24T09:50:19-0400
The law of the isothermal process (Boyle): for a given mass of gas at a constant temperature of product of pressure and volume is constant. p1V1 = p2V2 773.6 mm Hg * 1.397 L = 1.030L * p2 p2 = 773.6 mm Hg * 1.397 L / 1.030L; p2 = 1049.24 mm Hg p2 = 1049.24 mm Hg / 760 mm Hg = 1.38 atmospheres
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