Aluminum reacts with oxygen. What is the balanced equation? If 1.295 g of aluminum reacts with 0.48 g of oxygen, how many grams of aluminum oxide are formed? Identify the limiting reactant. Include balanced equation, molar mass values, dimensional analysis, and limiting reactant.
This is the balanced equation.
We have given that,
1.295g of Aluminum reacts with 0.48g of Oxygen
No. of moles of Al = = 0.048
No. of moles of oxygen= = 0.031
For 4 moles of Al we need 3 moles of
0.048 moles of Al we need 0.03 moles of
Therefore some oxygen is left behind
Hence, Aluminum is limiting reagent.