Answer to Question #167364 in Inorganic Chemistry for Jeanette

Question

Compute for the molar solubility of cadmium hydroxide which is slightly soluble in water if the Ksp value is 6.0 x 10^-12.

Answer 1

From the balanced net ionic equation;

$Cd^{2+}_{(aq)}+2OH^{-}_{(aq)}\leftrightharpoons Cd(OH)_{2_{(aq)}}$

$K_{sp}=[Cd^{2+}][OH^-]$

$6.0\times 10^{-12}=(x).(2x^2)$

$4x^3=6.0\times 10^{-12}$

$x^3=1.5\times 10^{-12}$

$x=3.67\times 10^{-6}$ $M$