Answer to Question #166699 in Inorganic Chemistry for Richard

Question #166699

Sulfur (1400 kg) and pearl caustic soda (950 kg) are reacted to form sodium polysulphide (Na2Sx) to a total of 4000 L (balanced by H2O). What percentages (%) of total sulphur (S), sodium sulphide (Na2S), sodium thiosulphate (Na2S2O3) and sodium sulfur compounds are in solution?


1
Expert's answer
2021-02-26T05:55:41-0500


Moles of Sulphur =

Moles of NaOH =

From reaction,

6 moles of NaOH react with 4 moles of S

23.75 kmol of NaOH reacts with 15.833 kmol of S

Moles of S left = 43.75 - 15.833 = 27.91 kmol

Total volume of Solution = 4000 L

Moles of Na2S2O3 formed = 3.95 kmol

Moles of Na2S formed = 7.91 kmol

Moles of H2O formed = 11.87 kmol

Mass of S left =

Mass of Na2S2O3 formed =

Mass of Na2S formed =

Mass of H2O formed =

Mass/Volume percentage of components,

(since H2O is added externally also)


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