Answer to Question #165705 in Inorganic Chemistry for jovana

Question

how much CuSo4x5H20 and how much H20 do you need to make 500g 10% CuSo4

Answer 1

The mass of pure CuSO₄ needed for the solution equals $500g\times0.1=50g$

The mass of CuSO₄*5H₂O can be calculated:

$50g_{CuSO_4}\times\frac{1mol_{CuSO_4}}{159.61g_{CuSO_4}}\times\frac{1mol_{CuSO_4\cdot5H_2O}}{1mol_{CuSO_4}}\times\frac{249.69g_{CuSO_4\cdot5H_2O}}{1mol_{CuSO_4\cdot5H_2O}}=78g_{CuSO_4\cdot5H_2O}$

Therefore, the mass of H₂O equals $500-78=422g$

Answer: 78 g CuSO₄*5H₂O and 422 g H₂O