Answer to Question #163607 in Inorganic Chemistry for Ahmed Ismail

Question #163607

I take 1g of zinc metal and after dissolving, diluting it to 500 ml and adjust the PH of 50 ml of it to make titration with an unknown concentration of EDTA.

I found 1g of zinc took 25 ml of EDTA that means 0.004 g of zinc equivalent to 1ml of unknown concentration of EDTA.

My question is how can I calculate the concentration of EDTA from the above information?



1
Expert's answer
2021-02-15T03:21:51-0500

1mL = 0.001L.

n=m/Mr = 0.004/65 = 6,15384615e-5 moles of Zn.

And Zn and EDTA equal.

Cm=n/V= 6,15384615e-5/0.001 = 0,0615384615 M.


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment

Ask Your question

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS