Answer to Question #162178 in Inorganic Chemistry for Bailey

Question

Determine the number of atoms of O in 22.3 moles of Al2(CO3)3

Answer 1

One formula unit of Al₂(CO₃)₃ contains 9 atoms of oxygen.

Therefore, the number of O atoms in 22.3 moles equals:

$9\times22.3\times6.022\cdot10^{23}=1.21\cdot10^{26} atoms$

Answer: $1.21\cdot10^{26}$