Answer to Question #160122 in Inorganic Chemistry for Ling Shing Jing

Question #160122

The hybridization of B in the BF3 molecule is


1
Expert's answer
2021-02-01T03:59:50-0500

SP2 hybridization


Explanation:

BF3 has a boron atom with three outer-shell electrons in its ground state and three fluorine atoms containing seven outer electrons. Further, if we observe closely, one boron electron is unpaired in the ground state. During the formation of this compound, the 2s orbital and two 2p orbitals hybridize. Only one of the empty p-orbital is left behind as the lone pair. In short, Boron needs 3 hybridized orbitals to make bonds with 3 atoms of F where the 2pz orbitals get overlapped with these hybridized sp2 orbitals and bonds are formed.


NB:

  • The three hybridized sp2 orbitals are usually arranged in a triangular shape.
  • BF3 molecule is formed by bonding between three sp2 orbitals of B and p of 3 F atoms.
  • All the bonds in BF3 are sigma bonds.

Reference

RAO, K. V. (1964). Chemical Bonding.


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