Question #15623

calculate % ionic character of K---Cl bond in KCL. electro negativity of K and CL are 0.8, and 3.0 respectively

Expert's answer

% ionic = [1-e^(-1/4)(a-b)]100

[1-e^(-1/4)(3.0-0.8)]100 = 48.66%

e is base of natural log

a-b is the difference between electronegativity values of the 2 atoms

[1-e^(-1/4)(3.0-0.8)]100 = 48.66%

e is base of natural log

a-b is the difference between electronegativity values of the 2 atoms

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