I take 5g of solid-liquid mixture sample,after acid digestion and make up to 50ml,from which I take 10 ml for chloride analysis,there 0.2ml AgNO3 consumed after back titration against 0.02N AgNO3 and NH4SCN.
how to calculate the chloride in the original sample? unit of result as mg/L or mg/kg?
molarity × number of hydrogen ions = normality
molarity × 1 = 0.02N
Therefore, molarity of AgNO3 = 0.02M
molar mass of HCl = 36.5g/mol
molar concentration = 0.0004M
mass concentration = molar mass × molar concentration = 36.5 × 0.0004 = 0.0146 g/L = 14.6mg/L
Therefore, the concentration of the chloride in the original sample is 14.6mg/L.