Answer to Question #153930 in Inorganic Chemistry for Morayo

Question

What is the amount of gold present in 15.5g of a pure gold wedding ring.(Au=197)

Answer 1

Solution:

$\nu=\frac{m} {A} =\frac{15.5 g} {197 g/mol} =78.68\times10^{-3}mol$

Answer: $78.68\times10^{-3}mol$