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Answer to Question #15382 in Inorganic Chemistry for Ashley

Question #15382
Aluminum will react with bromine to form aluminum bromide (Al2Br6). What mass of bromine (g) is needed to form 1.47 mol of Al2Br6?
Expert's answer
3x mol 1.47 mol
2Al+3Br2--->Al2Br6

3x=1.47
x=0.49 mol

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