Answer to Question #152418 in Inorganic Chemistry for dianne

Question #152418
balanced equation of p + cu2+ -> cu + h2po4
1
Expert's answer
2020-12-22T04:33:31-0500

P in P has an oxidation state of 0

P in H2PO4 has an oxidation state of +6

So, P in P is oxidized to H2PO4

Cu in Cu+2 has an oxidation state of +2

Cu in Cu has an oxidation state of 0

So, Cu in Cu+2 is reduced to Cu

Reduction half cell:

Cu+2 + 2e- → Cu

Oxidation half cell:

P → H2PO4 + 6e-

Balance number of electrons to be same in both half-reactions

Reduction half cell:

3Cu+2 + 6e- → 3Cu

Oxidation half cell:

P → H2PO4 + 6e-

Let's combine both the reactions.

3Cu+2 + 1P → 3Cu + 1H2PO4

Balance Oxygen by adding water

3Cu+2 + 1P + 4H2O → 3Cu + 1H2PO4

Balance Hydrogen by adding H+

3Cu+2 + 1P + 4H2O → 3Cu + 1H2PO4 + 6H+

This is balanced chemical equation in acidic medium

Answer: 3Cu2+ + P + 4H2O --> 3Cu + H2PO4 + 6H+

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment

Ask Your question

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS