Answer to Question #152297 in Inorganic Chemistry for ANJALI

Question

you are provided KMnO4 solution which is about N/100. however you prepared standard solution of mohr salt which is about N/20, can 10ml of this standard mohr salt solution be used fot tiitrating with given KMnO4

Answer 1

The overall chemical equation in titration of Mohr salt with KMnO₄ is

$2KMnO_4 + 10FeSO_4(NH_4)_2SO_4.6H_2O+8H_2O \to K_2SO_4+ 2MnSO_4+ 5Fe_2(SO_4)_3+ 10(NH_4)_2SO_4+ 68H_2O$

number of moles of Mohr Salt used = normality × volume = 1/20 × 10/1000 = 1/2000 moles.

from the reaction above, 10 moles of Mohr Salt reacts with 2 moles of KMnO₄.

Therefore, 1/2000 moles of Mohr Salt reacts with 1/10000 moles of KMnO_4.

volume of KMnO₄ = number of moles/normality

= 1/10000 ÷ 1/100 = 1/100L = 10mL

This means that 10ml of this standard mohr salt solution be used fot tiitrating with given 10ml of this standard mohr salt solution be used fot tiitrating with given KMnO₄ solution, provided it's volume is 10mL or above.