Answer to Question #143053 in Inorganic Chemistry for trisha

Question

What is the % O in potassium permanganate, KMnO4?

Answer 1

$\begin{aligned} \textsf{mass of }KMnO_4 &= 39+55+4(16)\\ &= 158g\\ \textsf{mass of Oxygen in }KMnO_4 &= 4(16)\\ &= 64g\\ \\ \%\textsf{ mass of Oxygen} &= \dfrac{\textsf{mass of Oxygen}}{\textsf{mass of }KMnO_4} × 100\% \\ \\ &= \dfrac{64}{158} × 100\% \\ \\ &= 40.51\% \end{aligned}$