Answer to Question #142292 in Inorganic Chemistry for Sarita bartwal

Question #142292
Draw the MO energy level diagram of NO and calculate its bond order
1
Expert's answer
2020-11-09T11:57:06-0500

Electronic configuration of nitrogen is 1s2 2s2 2p3


Electronic configuration of oxygen is 1s2 2s2 2p4


Thus, total number of electrons present in molecule is 15


The molecular orbital energy-level diagram of molecule is as follows






Bond order =1/2(no. of BMO-no. of anti ABMO)


For NO total no.of electron=15


no. of anti bonding electron=5


no. of bonding electron=10


1/2(10–5)=2.5


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