Answer to Question #141934 in Inorganic Chemistry for Olebogeng

Question #141934

Describe the bonding in both the superoxide ion (O2-) and the peroxide ion (O22-) in terms of molecular orbital theory, and compare their bond order to that of O2

Expert's answer

Bond order of the following is: O22−=1,O2−=1.5,O2=2,O2+=2.5

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Answer to Question #141934 in Inorganic Chemistry for Olebogeng

Bond order of the following is: O22−​=1,O2−​=1.5,O2​=2,O2+​=2.5

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Related Questions

Bond order of the following is: O22−=1,O2−=1.5,O2=2,O2+=2.5